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Apetreigabriel
a fost răspuns

a=1+2+3+....+100+51x101

Răspuns :

Andreutzakriss
1+2+3+...+n[tex]= \frac{n(n+1)}{2} [/tex]
a=1+2+3+...+100+51x101
a=100*101/2+51*101
a=50*101+51*101
a=101(50+51)
a=101*101=101²-patrat perfect
A=1+2+3+....+100+51*101
A=100*(100+1):2+51*101
A=100*101:2+51*101
A=50*101+51*101
A=101(50+51)
A=101*101
A=101²=patrat perfect

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