S1
ex 1. 3+2-5=0 (adevarat)
log₂(2^3)=3
(1/2)^(-1)=2
[tex] \sqrt[3]{ 5^{3} } [/tex] =5
2. Apartine graficului=> verifica ec:
Ya=2012*Xa-2011 <=> 2=2012*(2013/2012)-2011 <=> 2= 2013-2011 (Adevarat)
3.Combinari de 5 luate cate 3 (Cred)
4. Pe 4^x il poti scrie ca 2^(2x)
Notand 2^x=t =>
t^2-10t+16=0
delta=100-64=36
t1/2=(10 +sau- 6)/2 => t1=8 => x=3
=> t2=2 => x=1
