Răspuns :
[tex]\it log_62=a,\ \ \ log_36=?[/tex]
[tex]\mathcal{R:}[/tex]
[tex]\it log_3 6=\dfrac{log_6 6}{log_6 3} =\dfrac{1}{log_6 \frac{6}{2}}=\dfrac{1}{log_6 6 -log_6 2} =\dfrac{1}{1 - a}[/tex]
[tex]\mathcal{R:}[/tex]
[tex]\it log_3 6=\dfrac{log_6 6}{log_6 3} =\dfrac{1}{log_6 \frac{6}{2}}=\dfrac{1}{log_6 6 -log_6 2} =\dfrac{1}{1 - a}[/tex]