Răspuns :
( _x+2_ - _x- 3_ - ____25___ ) : _ 5__ =
x-3 x+ 2 (x- 3)( x+ 2 x+ 2
( _(x+2)(x+ 2)_- _(x- 3)( x- 3)_ - ____25___ ) : _ 5__ =
(x- 3)( x+ 2 x+ 2
_( x²+ 4x+ 4- x²+ 6x- 9- 25)_ : _5_ =
(x- 3) ( x+ 2) (x+ 2)
_ _10x- 30____· _x+ 2_ =
(x- 3) ( x+ 2) 5
_10( x- 3)_ · _1_ =
x- 3 5
2
x-3 x+ 2 (x- 3)( x+ 2 x+ 2
( _(x+2)(x+ 2)_- _(x- 3)( x- 3)_ - ____25___ ) : _ 5__ =
(x- 3)( x+ 2 x+ 2
_( x²+ 4x+ 4- x²+ 6x- 9- 25)_ : _5_ =
(x- 3) ( x+ 2) (x+ 2)
_ _10x- 30____· _x+ 2_ =
(x- 3) ( x+ 2) 5
_10( x- 3)_ · _1_ =
x- 3 5
2