Răspuns :
100 kg sol.....10kg NaOH
1,2 kg sol.......x=0.12kg
100kg sol.......40kg NaOH
1,8kg sol........y=0.72kg
ms=1,2+1,8=3 kg
m=x+y=0,12+0,72=0,84 kg
3 kg sol..........0,84kg NaOH
100 kg sol.........z=28% deci C
1,2 kg sol.......x=0.12kg
100kg sol.......40kg NaOH
1,8kg sol........y=0.72kg
ms=1,2+1,8=3 kg
m=x+y=0,12+0,72=0,84 kg
3 kg sol..........0,84kg NaOH
100 kg sol.........z=28% deci C
Cp1=md1/ms1*100==>md1=Cp1*ms1/100=10*1.2/100=0.12kg NaOH
Cp2=md2/ms2*100==>md2=0.72kg NaOH
mdf=md1+md2=0.12+0.72=0.84kg
msf=ms1+ms2=1.2+1.8=3kg
Cpf=mdf/msf*100=0.84/3*100=28%
Cp2=md2/ms2*100==>md2=0.72kg NaOH
mdf=md1+md2=0.12+0.72=0.84kg
msf=ms1+ms2=1.2+1.8=3kg
Cpf=mdf/msf*100=0.84/3*100=28%