L=lungimea bazei
l=latimea bazei
h=inaltimea
h=√L×l ⇒ h²=L×l
diagonala bazei paralelipipedului =√(L²+l²)
P=2(L+l)=26 L+l=13 L²+2L×l+l²=169 L²+l²=169-2L×l
L²+l²-2h²=25
L²+l²-2L×l=25
169-2L×l-2L×l=25
4L×l=144
L×l=36
L+l=13
36=9×4
9+4=13
L=9 cm
l=4 cm
h=√9×4=√36=6 cm
b)
At=2(9×4+9×6+4×6)=2(36+54+24)=288 cm²
c)V=9×4×6=216 cm³
