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aflati media aritmetica a numerelor 12si 24 ., 14,42si 100 . 90 ,110,121 si 3.

Răspuns :

EricPop15
(12+24):2=
36:2=18

(12+42+100):3=
154:3=51,(3)

(90+110+121+3):4=
324:4=81
(12+24):2=
=38:2=19

(14,42+100):2=
=114,42:2=57,21

(90+110+121+3):4=
=(200+121+3):4=
=(321+3):4=
=324:4=81