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Oanaelena98
a fost răspuns

numarul N=3^2011+2*3^2010+3^2009+3^2008 este patrat perfect

Răspuns :

CarMina03
3²°¹¹+2*3²°¹°+3²°°⁹+3²°°⁸=3²°°⁸x(3³+2*3²+3+1)=3²°°⁸x(27+18+3+1)=3²°°⁸x49=(3¹°°⁴)²x7²
produs de doua patrate perfecta da patrat perfect
AlecSanDaRu
[tex] 3^{2011} +2* 3^{2010} +3^{2009} + 3^{2008} =3^{2008}( 3^{3}+2* 3^{2}+ 3+1)[/tex]=[tex]3^{2008}(27+18+4)=3^{2008}*49=3^{2008} *7^{2} =(3^{1004}*7)^2[/tex] => N pp

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