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Madalaina556
a fost răspuns

cati moli de acid sulfuric sunt continuti in 6 kg solutie 3.2 la suta

Răspuns :

Corneadiana23
msH2SO4=6kg=6000g
c=3,2%
______________
?nH2SO4
______________
c=md/ms*100
md=c*ms/100
md=3,2*6000/100=192g
MH2SO4=2+32+64=98g/mol
n=m/M=192/98mol
Marianamariana6
c%=md*100/msol
.md=4.9*8/100=0.392kg
Nr moli=m/M
Nr moli=0.392*1000/98=4 moli

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