Răspuns :
a - nr de kg mere primul cos
b - nr kg mere al doilea cos
a + b = 82 atunci a = 82-b
a-14 = 5 x (b - 20 )
a-14 = 5b-100
82-b-14 = 5b - 100
68-b=5b-100
68+100 = 5b+b
168=6b
b=168:6
b=28
a=82-28
a=54
b - nr kg mere al doilea cos
a + b = 82 atunci a = 82-b
a-14 = 5 x (b - 20 )
a-14 = 5b-100
82-b-14 = 5b - 100
68-b=5b-100
68+100 = 5b+b
168=6b
b=168:6
b=28
a=82-28
a=54