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Yonutache
a fost răspuns

1  aratati ca n=27⁹·32¹¹:2-16⁶·2·6²⁷ este patrat perfect

Răspuns :

CarMina03
n=27⁹·32¹¹:2-16⁶·2·6²⁷
n=(3³)⁹·(2⁵)¹¹:2-(2⁴)⁶·2·2²⁷·3²⁷

n=3²⁷·2⁵⁵:2-2²⁴·2·2²⁷·3²⁷

n=3²⁷·2⁵⁴-2⁵²·3²⁷

n=3²⁷·2⁵²·(2²-1)

n=3²⁷·2⁵²·3
n=3²⁸·2⁵²
n=(3¹⁴)²·(2²⁶)²