Răspuns :
a=km parcursi ziua 1
b=km parcursi ziua 2
(a+b)/2=km parcursi ziua 3
a+b+(a+b)/2=291
2a+2b+a+b=582
3(a+b)=582
a+b=194
(a+b)/2=194/2=97 km
b=km parcursi ziua 2
(a+b)/2=km parcursi ziua 3
a+b+(a+b)/2=291
2a+2b+a+b=582
3(a+b)=582
a+b=194
(a+b)/2=194/2=97 km
a+b+c =291
a+b/2 =c ; a+b =2c inlocuim in prima relatie obtinem
2c +c =291
3c =291
c=291: 3
c =97 km
a+b/2 =c ; a+b =2c inlocuim in prima relatie obtinem
2c +c =291
3c =291
c=291: 3
c =97 km