56g.................................158g
CaO+ 2CH3COOH---> (CH3COO)2Ca +H2O
20g.................................m=56,4g-valoare teoretica
m=39,5g-valoare practca
randamentul= m,practicx100/ m,teoretic=> 39,5x100/56,4= calculeaza !!!!
M,CaO= 56
M,acetat de calciu= 158g/mol
Cred ca problema mai are o cerinta, pentru ca se da c=10% ?????
