1. a) AC=l√2=8√2cm
AO= AC/2=4√2cm
ΔVOA-drerunghic in O ⇒VB²=AO²+VO²=32+9=41⇒VB=√41
Sm(suma muchiilor)=4xAB+4xVB= 32 + 4√41 =32 +25,61 = 57,61cm
b) At = Al + Ab=80+64=144cm²
Ab=l²=64cm²
Al=Pb x VM( apotema piramidei)/ 2= 32 x 5 /2 =80cm²
Pb=4xl=32cm
Constuim VM⊥BC si OM⊥BC, M∈BC
ΔVOM-dreptunghic in O ⇒ VM²=OM²+VO²=16+9=25⇒VM=5cm
OM=l/2=4cm
