-masa de KCl din solutie
c/100= md/ms
20/100= md/104,5----> md= 20.9gKCl
n=m/M; n=20,9g/(39+35,5)g/mol= 0,28molKCl
1 mol 1mol 1mol 1mol
KCl + AgNO3---> AgCl ↓ +KNO3
0,28mol......0,28....0,28......0,28
m=0,28XM, unde M este masa molara a sarii care te intereseaza cred ca AgCl !!!!!!
