Construim,un,Δ,isoscel,cu,laturile=r=24cm,si,baza=coardaAC
Stim,ca,masura,arcului,AB+masura,arcului,BC=120°=>m(∡AOC)=120°
=>masurile,unghiurilor,de,la,baza,Δisoscel=30°
Ducem,OM_l_AC(M∈AC)
Avem,ΔOMCdr.
OM,este,cateta,opusa,∡30°=>OM=OC/2=12cm
Cu,t.Pit.,calculam,MC
MC²=OC²-OM²
MC²=576-144
MC²=432
MC=12√3=AM=>AC=24√3cm