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Byutzabya
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Ajutati-ma si cu astea plz:
(-3)'3 *[(-7)'2 -10x]=(-3)'4 x
(-4)'3*[(-5)'3 +13x]=(-2)'5 x
(-2)'5*[3x+(-3)'2*7]=(-2)'4 x
(-5)'2*[2x-(-2)'3]=(-4)'2*3x
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Răspuns :

Capsunica35
(-3)³*[(-7)²-10x]=(-3)^4x
-27*[14-10x]=81x
14-10x=81x:(-27)
-10x=-3x-14
-10x+3x=-14
-7x=-14
x=14/7
x=2

(-4)³*[(-5)³+13x]=(-2)^5x
-64*[-125+13x]=-32x
-125+13x=-32x:(-64)
13x=0,5x+125
13x-0,5x=125
12,5x=125
x=125:12,5
x=10

(-2)^5*[3x+(-3)²*7]=(-2)^4x
-32*[3x+63]=16x
3x+63=16x:(-32)
3x=0,5x-63
3x-0,5x=-63
2,5x=-63
x=-63:2,5
x=-25,2

(-5)²*[2x-(-2)³]=(-4)²*3x
25*[2x+8]=16*3x
2x+8=48x:25
2x=1,92x-8
2x-1,92x=-8
0,08x=-8
x=-8/0,08
x=-100