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a fost răspuns

Descompuneti in factori
1)x^2-4x-12
2)x^2-2x-3
3)x^4-x^2-6
4)x^2-x-6
5)x^2+2x-15
6)16x^2-40x+25
7)x^2+2x-8
8)(2x^2-x)+(2x^2-x-2)-8
9)2x^2-5x+2
10)16x^2-40+25
11)2x^2-x-3
12)x^2-5x-6

Va implooor

Răspuns :

Renatemambouko
1)x²-4x-12=x²-6x+2x-12=x(x-6)+2(x-6)=(x-6)(x+2)
2)x²-2x-3=x²+x-3x-3=x(x+1)-3(x+1)=(x+1)(x-3)
3)x⁴-x²-6=x⁴+2x²-3x²-6=x²(x²+2)-3(x²+2)=(x²+2)(x²-3)=(x²+2)(x-√3)(x+√3)
4)x²-x-6=x²+2x-3x-6=x(x+2)-3(x+2)=(x+2)(x-3)
5)x²+2x-15=x²-3x+5x-15=x(x-3)+5(x-3)=(x-3)(x+5)
6)16x²-40x+25=(4x-5)²
7)x²+2x-8  =x²+4x-2x-8=x(x+4)-2(x+4)=(x+4)(x-2)
8)(2x²-x)+(2x²-x-2)-8 =4x²-2x-10=2(2x²-x-5)
9)2x²-5x+2=2x²-4x-x+2=2x(x-2)-(x-2)=(x-2)(2x-1)
10)16x²-40x+25=(4x-5)²
11)2x²-x-3=2x²-3x+2x-3=x(2x-3)+(2x-3)=(2x-3)(x+1)
12)x²-5x-6=x²-6x+x-6=x(x-6)+(x-6)=(x-6)(x+1)

























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