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Lecavalentin
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Log2. (2x+1)=log2. 5 rezolvare va rog doiul de la log e indice. Urgent

Răspuns :

   
[tex]log_2(2x+1) = log_2(5) \\ \\ 2x+1 = 5 \\ \\ 2x = 5-1 \\ \\ 2x = 4 \\ \\ \displaystyle x = \frac{4}{2} = \boxed{2}[/tex]
[tex]\displaystyle log_2(2x+1)=log_25 \\ C.E.~~2x+1\ \textgreater \ 0 \Rightarrow x\ \textgreater \ - \frac{1}{2} \\ 2x+1=5 \\ 2x=5-1 \\ 2x=4 \Rightarrow x= \frac{4}{2} \Rightarrow x=2[/tex]

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