Răspuns :
2x²-5x=3
2x²-5x-3=0
Δ=b²-4ac
Δ=25+24
Δ=49
√Δ=7
x₁=(5-7)4=(-2/4)=(-1/2)
x₂=(5+7)/4=3
2x²-5x-3=0
Δ=b²-4ac
Δ=25+24
Δ=49
√Δ=7
x₁=(5-7)4=(-2/4)=(-1/2)
x₂=(5+7)/4=3
Sa iti dau si cealalta varianta
[tex]2x^{2}-5x-3=0\Rightarrow 2x^{2}-6x+x-3=0\Rightarrow 2x(x-3)+x-3=0\Rightarrow (2x+1)(x-3)=0\Rightarrow x\epsilon 3,-\frac{1}{2}[/tex]
[tex]2x^{2}-5x-3=0\Rightarrow 2x^{2}-6x+x-3=0\Rightarrow 2x(x-3)+x-3=0\Rightarrow (2x+1)(x-3)=0\Rightarrow x\epsilon 3,-\frac{1}{2}[/tex]