a) 2KMnO4 + 3H2SO4 + 5H2O2 --> K2SO4 + 2MnSO4 + 8H2O + 5O2
Mn(+7) +5e --> Mn (+2) se reduce (ag ox.)
O2 (-1) -1e --> O2 (0) se oxideaza (ag. red)
b) Cm=md/M×Vs
ms=md+mH2O=63.6+400=463.6g
ro (densitatea)= ms/Vs==>Vs=ms/ro=463.6/1.3=356.615cm3=0.356L
MKMnO4=158g/mol
Cm=63.6/158*0.356=63.6/56.248=1.13 moli/L
c) Cp=md/ms*100==> md=Cp×ms/100=8×500/100=40g KCl
MKCl=74.5g/mol
n (nr moli)= md/M=40/74.5=0.5369 moli KCl