Răspuns :
a+b+c=145 relatia (1)
b=3a+4 relatia(2)
c=2b+3 relatia(3)
Relatia (2) b=3a+4 o introducem in relatia (3) si obtinem: c=2(3a+4)+3, adica c=6a+8+3 rezulta c=6a+11. Aceasta relatie obtinuta, impreuna cu relatia (2) le introducem in prima relatie si obtinem:
a+3a+4+6a+11=154 adica 10a=130, rezulta a=13, b=43, c=89
b=3a+4 relatia(2)
c=2b+3 relatia(3)
Relatia (2) b=3a+4 o introducem in relatia (3) si obtinem: c=2(3a+4)+3, adica c=6a+8+3 rezulta c=6a+11. Aceasta relatie obtinuta, impreuna cu relatia (2) le introducem in prima relatie si obtinem:
a+3a+4+6a+11=154 adica 10a=130, rezulta a=13, b=43, c=89
a+b+c=145
b:a=3+r4 b=3a+4
c:b=2+r3 c=2b+3=2*(3a+4)+3=6a+8+3=6a+11
a+3a+4+6a+11=145
10a=145-15
a=130:10
a=13
b=3*13+4=39+4=43
b=43
c=6*13+11=78+11=89
c=89
b:a=3+r4 b=3a+4
c:b=2+r3 c=2b+3=2*(3a+4)+3=6a+8+3=6a+11
a+3a+4+6a+11=145
10a=145-15
a=130:10
a=13
b=3*13+4=39+4=43
b=43
c=6*13+11=78+11=89
c=89