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Adelinasavin
a fost răspuns

(2x+3)^2-3x(1-x)+2(x-+3)(x-3)-(3x-2)^2=?

Răspuns :

DARIA20011
(2x+3)^2-3x(1-x)+2(x+3)(x-3)-(3x-2)^2=
4x^2+12x+9-3x+3x^2+2(x^2-9)-(9x^2-12x+4)=
7x^2+9x+9+2x^2-18-9x^2+12x-4=
9x^2+21x-9-9x^2-4=
21x-13

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