Răspuns :
(x+2)²-(x-3)(x+3)=x
x²+4x+4-(x²-9)=x
x²+4x+4-x²+9=x
x²-x²+4x-x+4+9=0
3x+13=0
3x=-13
x=-13/3
x=-4,(3)
x²+4x+4-(x²-9)=x
x²+4x+4-x²+9=x
x²-x²+4x-x+4+9=0
3x+13=0
3x=-13
x=-13/3
x=-4,(3)
[tex]\it (x+2)^2 -(x-3)(x+3) =x \Leftrightarrow x^2+4x+4 -x^2+9=x[/tex]
[tex]\it 4x - x = -9 - 3 \Leftrightarrow 3x = -13 \Leftrightarrow x = -\dfrac{13}{3}[/tex]
[tex]\it 4x - x = -9 - 3 \Leftrightarrow 3x = -13 \Leftrightarrow x = -\dfrac{13}{3}[/tex]