👤
Deni789
a fost răspuns

Aflati x din : 1+2+3....+2004/2+4+6+...+2004= 2x-1/x
dau coroana!

Răspuns :

RichardPurdel03
1+2+3+...+2004= (1+2004)*2004/2=2005*1002
2+4+6+...+2004=
=(2+2004)*1002/2=
=1003*1002
Ecuaţia devine:
2005*1002/1003*1002=2x-1/x
2005/1003=2x-1/x
Ecuația devine:
2005*x=2006*x-1003
2006*x-2005*x=1003
x=1003

Alte intrebari