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DANUSIA1
a fost răspuns

1+{2+3×[4+5×(6-x)]÷7}÷8 = 2

Răspuns :

DARIA20011
1+{2+3×[4+5×(6-x)]÷7}÷8 =2
{2+3×[4+5×(6-x)]÷7}÷8 =2-1
2+3×[4+5×(6-x)]÷7=1×8
3×[4+5×(6-x)]÷7=8-2
[4+5×(6-x)]÷7=6÷3
4+5×(6-x)=2×7
5×(6-x)=14-4
6-x=10÷5
6-x=2
x=6-2
x=4

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