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Va rog ajutoor!!
[tex] \frac{1}{6} x(x-2)(x-1) + \frac{x(x-3)(x-2)(x-1)}{24} = x(x-2)
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Răspuns :

Renatemambouko
x/6 ×(x-2)(x-1) +x(x-3)(x-2)(x-1)/24=x(x-2)
1/6 ×(x-1) +(x-3)(x-1)/24=1
(x-1)/6  +(x-3)(x-1)/24=x
4(x-1)+(x-3)(x-1)=24
4x-4+x²-3x-x+3=24
x²-1=24
x²=25
x=5
x=-5