f(x)=-x²+2x+24 a=-1 , b=2 c=24 a=-1<0 , functia admite un maxim Vmax=-b/2a=(-2)/(-2)=1 f(-1)=-Δ/4a=-1-2+24=21 Vmaxde coordonate (1 ,21) Im f= (-∞,21] Intersectia cu axa Ox f(x)=0 rezolvi ecuatia si obtii x1=-4 ,x2=6 Int cu Oy f(0)=24 Trasezi graficul