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Valentina72
a fost răspuns

3 la n *2 la 2n+1+3 la n+2*4 la n+1 se divide cu 42

Răspuns :

Renatemambouko
3^(n+1)×2^(2n+1)+3^(n+2)×4^(n+1)=
=3^(n+1)×2^(2n+1)+3^(n+2)×2^(2n+2)=
=3^(n+1)×2^(2n+1)×(1+3^1×2^1)=
=3^(n+1)×2^(2n+1)×7=
=3^n ×3×2^2n×2×7=
=3^n ×2^2n ×6×7=
=3^n ×2^2n ×42 deci divizibil cu 42



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