a)Fie x si y salariile celor doi muncitori
x+x×33.(3)%=2×y => x×9/9+x×3/9=y×2 =>
x×12/9=y×2 /:2 =>
x×6/9=y }=>
dar x+y=2000 }=>
x+x×6/9=2000 =>
x×15/9=2000 =>
x=1200 =>
y=200-x=2000-1200=800
Deci,primul muncitor castiga 1200 de lei iar al doilea 800 de lei
b)(x+50%×x)/(y+50%×y)-x/y
=(3/2×x)/(3/2×y)-x/y
=x/y-x/y (prima fractie se simplifica cu 3/2)
=0