p=95%
M=124g/mol CuCO3; M= 18g/molH20; M= 135g/molCuCl2
c/100= md/ms-->36,5/100=md/400--> md= 146gHCl; m,apa= 400-146
n=m/M; n= 146g/36,5g/mol=4molHCl
1mol 2mol 1mol 1mol 1mol
CuCo3 + 2HCl---> CuCl2 + H2O+ CO2
2mol........4mol..........2mol.......2mol
m=nxM; m=2molx124g/mol= 248gCuCO3pur
p/100=mpur/mimpur; 95/100= 248/mimpur---------------> calculeaza m,impur
in solutia formara se gasesc:
m= nxM=2molx135g/mol= 270gCuCl2=> masa dizolvata. md
m,apa= m,apa formata + m,apa de la sol.acid
= 2x18g + (400-146)g=290g
ms= md+m,apa= 270+290=>560g
c/1oo=md/ms--> c= 270x100/ 560---------------> calculeaza c !!
