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Ilieadryan
a fost răspuns

Calculati c.m.m.m.c al numerelor:81^12+9^24 si 27^15+3^45

Răspuns :

81^12+9^24=(3^4)^12+(3²)^24=3^(4·12)+3^(2·24)=3^48+3^48=3^48(1+1)=
=3^48·2
27^15+3^45=(3³)^15+3^45=3^45+3^45=3^45(1+1)=3^45·2
[2·34^48, 2·3^45]=2·3^48

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