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a fost răspuns

ecuatia de gradul2 x la patrat+2x+1

Răspuns :

[tex] x^{2} +2x+1=[/tex]

a=1
b=2
c=1

Δ=[tex] b^{2} -4ac[/tex]
  = 4-4
  =0
[tex] \sqrt{} [/tex]Δ=0

[tex] x_{1}= \frac{-b- \sqrt{delta} }{2a}= \frac{-2-0}{2}= \frac{-2}{2} [/tex]=-1[tex] 

[tex] x_{2}= \frac{-b+ \sqrt{delta} }{2a}= \frac{-2+0}{2}= -\frac{2}{2}=-1 [/tex]

⇒ [tex] x^{2} +2x+1=(x+1)(x+1)= (x+1)^{2} [/tex]

Δ=delta


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