👤
Moly
a fost răspuns

Scrieti sub forma unei singure puteri cu exponent numar natural :
2 la 15 ×8 la 10×4 la 21. .
25 la 6×125 la 3 × 125 la 3
9 la 7x 27 la 3x3 la 13
a la 5x(a×b) la 5× b la 5
27 la 8: 81 la 2×3 la 21
36 la 5×6 la 5x 6 la x

Răspuns :

Renatemambouko
2^15 ×8^10×4^21 =2^15 ×2^30×2^42 =2^87
25^6×125^3 × 125^3 =5^12×5^9 × 5^9=5^30
9^7x 27^3x3^13=3^14x3^9x3^13=3^36
a^5x(a×b)^5× b^5=a^5 xa^5xb^5xb^5=a^10 x b^10
27^8: 81^2×3^21=3^24: 3^8×3^21=3^16x3^21=3^37
36^5×6^5× 6^x =(2^2×3^2)^5× (2^5×3^5)× (2^x × 3^x) =(2^10×3^10)× (2^5×3^5)× (2^x × 3^x) =2^(15+x) × 3^(15+x) 















Alte intrebari