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a fost răspuns

3,5^2-1,2x{11+1,1[6,5+2x(0,45-0,4)]}

Răspuns :

Iakabcristina2
3,5²-1,2x{11+1,1[6,5+2x(0,45-0,4)]}=
12,25-1,2x[11+1,1(6,5+2x0,05)]=
12,25-1,2x[11+1,1(6,5+0,1)]=
12,25-1,2x(11+1,1x6,6)=
12,25-1,2x(11+7,26)=
12,25-1,2x18,26=
12,25-21,912=
-9,662