Răspuns :
o metoda
3x(x-2)=0
x=0
x-2=0⇒x=2
aII-a metoda
a=3
b=-6
c=0
Δ=b²-4ac
Δ=36-12*0=36
x1=[tex] \frac{6+ \sqrt{36} }{6} = \frac{12}{6} =2[/tex]
x2=[tex] \frac{6- \sqrt{36} }{6} [/tex] =0
3x(x-2)=0
x=0
x-2=0⇒x=2
aII-a metoda
a=3
b=-6
c=0
Δ=b²-4ac
Δ=36-12*0=36
x1=[tex] \frac{6+ \sqrt{36} }{6} = \frac{12}{6} =2[/tex]
x2=[tex] \frac{6- \sqrt{36} }{6} [/tex] =0