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Daca stiu doar ca am n=2 moli Zn si am 2 M de HCl cum aflu Volumul molar de HCl si volumul de H2??

Răspuns :

65g...73g.........136g.....2g
Zn + 2HCl --> ZnCl2 + H2
130g..x=146g....y=272g... z=4g

n=m/M==>m=n*M=2*65=130g Zn4

Cm=md/M*Vs==>Vs=md/M/Cm=146/36.5/2=2 L HCl

n=m/M=4/2=2 moli H2

n=V/Vmolar==>V=n*Vmolar=2*22.4=44.8 L H2

MHCl=1+35.5=36.5g/mol
MH2=1*2=2g/mol
MZn=65g/mol
MZnCl2=65+2*35.5=136g/mol

Am notat "*" Inmultire si "/" linia de fractie..

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