1)Efectuati , respectand ordinea efectuarii operatiilor : (3x-1)²-2(x+2)²+3(1-x)(1+x)
2) Aratati ca : (x-2)(x+2)(x²+4)(x la puterea 4 +16 )(x la puterea 8 +256) = x la puterea 16 + 2 la puterea 16
1)(3x-1)²-2(x+2)²+3(1-x)(1+x)=(9x²-6x+1)-2(x²+4x+4)+3(1-x²)=9x²-6x+1-2x²-8x-8+3-3x²=4x²-14x-10=2(2x²-7x-5) 2)(x-2)(x+2)(x²+4)(x⁴+16)(x la a 8 +256)=xla a 16 - 2la a 16<=> (x²-4)(x²+4)(x⁴+16)(x la a 8 +256)=x la a 16-2 la a 16<=> (x⁴-16)(x⁴+16)(x la a 8+256)=x la a 16-2 la a 16<=> (x la a 8-256)(x la a 8+256)=x la a 16-2 la a 16<=> x la a 16 - 256²=x la a 16 - 2 la a 16<=> x la a 16 - 2 la a 16=x la a 16-2 la a 16(A)
Ai greșit tu acolo era x la a 16 - 2 la a 16 si nu plus intre ele.
