Prin Pitagora afli AC
BC²=AB²+AC²
100=36+AC²⇒AC²=64⇒AC=8 cm
[tex] sin C=\frac{AB}{BC} = \frac{6}{10} = \frac{3}{5} [/tex]
[tex] cos C=\frac{AC}{BC} = \frac{8}{10} = \frac{4}{5} [/tex]
[tex] tg B=\frac{AC}{AB} = \frac{8}{6} = \frac{4}{3} [/tex]
[tex]ctgB= \frac{AC}{AB} = \frac{3}{4} [/tex]
