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1. Sa se afle 4x+y/x+2y daca 3x+y/4x+3y=9/17
2. Aflati x,y,z daca x/3=y/6, y/2=z si x+2y+z=18

Răspuns :

Renatemambouko
(3x+y)/(4x+3y)=9/17
51x+17y=36x+27y
15x=10y
3x=2y
x/y=2/3
(4x+y)/(x+2y)= (4x/y+1)/(x/y+2)=(4×2/3+1)/(2/3+2)=(11/3)/(8/3)=
=11/3×3/8=11/8

2.
x/3=y/6  x=y/2    y=2x
y/2=z    x=z

 x+2y+z=18
x+2×2x+x=18
6x=18
x=3
y=2×3=6
z=3

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