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Se mononitreaza 300 g benzen de puritate 78 % cu amestec sulfonitric din sol de acid azotic de concentratie 80 % si acid sulfuric de concentratie 98 %. Masa de sol de acid azotic consumata este:

Răspuns :

Notez "*" inmultire si "/" impartire:

MC6H6=78g/mol
MH2SO4=98g/mol
MHNO3=63g/mol

p=mpur/mipur*100===>mpur=p*mimp/100=78*300/100=234g C6H6

78g............63g
C6H6 + HO-NO2/H2SO4 --->C6H5-NO2 + H2O
234g...........x=189g HNO3(md)

Cp=md/ms*100 ===>ms=md*100/Cp=189*100/80=236.25g HNO3

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