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Varogajutatima1
a fost răspuns

a la a doua - 4a+4 supra lu a la a doua +ab la a doua -2a-2b la a doua

Răspuns :

[tex]\dfrac{a^2-4a+4}{a^2+ab^2-2a-2b^2} = \dfrac{(a-2)^2}{(a^2-2a)+ (ab^2-2b^2)} = \dfrac{(a-2)^2}{a(a-2)+b^2(a-2)}\ . \\\;\\ =\dfrac{(a-2)^2}{(a-2)(a+b^2)}=\dfrac{(a-2)(a-2)}{(a-2)(a+b^2)} =\dfrac{a-2}{a+b^2}[/tex]


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