Cu teorema lui pitagora in ĪABC avem:
ACĀ²=BCĀ²-ABĀ²
ACĀ²=625-225
ACĀ²=400āAC=20 cm
AD=AB*AC/BC
AD=15*20/25
AD=12 cm
Cu teorema bisectoarei avem:
AC/AM=BC/BMāAC/BC=AM/BMā AC/AC+BC=AM/AB
ā20/20+25=AM/15 ā20/45=AM/15 ā AM=15*20/45=20/3 cm
Aabc= AB*AC/2 =15*20/2=150 cmĀ²
Aamc=AM*AC/2= (20/3*20)/2=200/3 cmĀ²
Aamc/Aabc=(200/3)/150=200/3*1/150=4/9