butenina : HC≡C-CH=CH2 n1 moli
butadiina : HC≡C-C≡CH n2 moli
52n1 + 50n2 = 152 26n1 + 25 n2 = 76
(4n1+ 2n2)·100/152 = 5,263 4n1 + 2n2 ≈ 8 2n1 + n2 = 4 n2 = 4- 2n1
26n1 + 100 - 50n1 = 76 24n1 = 24 n1 = 1 mol n2 = 2moli
n Na = n1 + 2n2 = 5moli
m Na pur = 5·23 = 115 g m Na 99% = 115·100/99 = 116,16 g