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rezolvati in R ecuatia:
a) (x-3)(x+4)-2(3x-2)=(x-4)la putrea 2

Răspuns :

Miky93
[tex](x-3)(x+4)-2(3x-2)=(x-4)^2 \\\\ \not x^2+4x-3x-12-6x+4=\not x^2-8x+16 \\\\ 4x-9x-8=-8x+16 \\\\ -5x+8x=16+8 \\\\ 3x=24 \ \ \ |:3 \\\\ \boxed{x=8}[/tex]

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