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Valeriaka10
a fost răspuns

alcatueste masa precipata formata la mesticat solutile continute clor de bariu cu masa 300 g si omega 5 % cu sulfat de sodiu

Răspuns :

1. Cp=md/ms*100 =>md=Cp*ms/100=5*300/100=15g BaCl2
MBaCl2=137+35.5*2=208g/mol
MNa2So=23*2+32+16*4=142g/mol
MBaSO4=137+32+16*4=233g/mol
208g...........142g.........233g
2. BaCl2 + Na2So4= BaSo4 + 2NaCl
15g...........xg.................y
x=10.24g Na2SO4
y=233*(10.24+15)/208+142=5880.92/350=16.8g BaSO4 




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