[tex]\it \mathcal{A} =\dfrac{AB\cdot AC \cdot \sin A}{2} =4\sqrt2 \Rightarrow \dfrac{4\cdot 4 \cdot \sin A}{2} =4\sqrt2 \Rightarrow \sin A =\dfrac{\sqrt2}{2}
\\\;\\
\Longrightarrow m(\hat{A}) =45^0[/tex]
Triunghiul fiind isoscel, celelalte doua unghiuri sunt congruente
si au masura de 135°
