-calculez masa de acid din solutia data
c/100=md/ms; 8/100= md/50---> md=4gHCl-;m,apa= 50-4 g
-ecuatia reactiei
1mol 2mol 2mol 1mol
K2O + 2HCl----> 2KCL + H2O
94g.......2x36,5g 2x74,5g.....18g sunt masele molare
m.............4g..............m'...............m"
m= 5,15g K2O; RAMAN nereactionate (2135-5,15)g
m'=8,16g KCl
m"=0,98gH20
iN FINAL se gaseste (2135-5,15) gK2O
8,16g KCl
0,98g apa
(50-4)g apa de la solutia de acid
nu prea cred ca ai 2135?????
ADUNI TOATE VALORILE-> M ,g
in Mg.........a,gK2O......8,16gKCl.....(0,98+46)g apa
in 100g..............x...................y....................z calculeaza x,y,z
