Răspuns :
(x-3)^2+2(x+1)=7
x²-6x+2x+2=7
x²-4x-5=0
Δ=b²-4ac=(-4)²-4*1*(-5)=16+20=36
x1,2=(-b+-√Δ)/2a=(-(-4)+-√36)/2*1=(4+-6)/2
x1=(4+6)/2=10/2=5
x2=(4-6)/2=-2/2=-1
x²-6x+2x+2=7
x²-4x-5=0
Δ=b²-4ac=(-4)²-4*1*(-5)=16+20=36
x1,2=(-b+-√Δ)/2a=(-(-4)+-√36)/2*1=(4+-6)/2
x1=(4+6)/2=10/2=5
x2=(4-6)/2=-2/2=-1