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Adelinaa96
a fost răspuns

Calculati concentratia molara a solutiei de acid azotic de concentratie 94% si densitatea=1,5 g/ cm3

Răspuns :

Cp=94%
ro=1,5g/cm3
Presupunem V=1L=1000cm3
ro=ms/V => ms=ro*V=1,5g/cm3*1000cm3=1500g
Cp=md/ms*100 =>md=Cp*ms/100=94*1500/100=1410g
MHNO3=1+14+48=63g/mol
Cm=md/M*Vs=1140/63*1=22.38 M (mol/L)

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